sin^2acos^2b - cos^2a sin^b
Answers
Answered by
3
sin^2a cos^2b - cos^2a sin^2b
= sin^2a (1 - sin^2 b) - (1 - sin^2a) sin^2b [Since cos^2x = 1 - sin^2x]
= sin^2a - sin^2a sin^2b -sin^2b + sin^2a sin^2b
= sin^2a - sin^2b
Answered by
0
sin2a.cos2b - sin2b.cos2a
sin2a.cos2 (90-b) - sin2b. cos2 (90-a)
sin2a.sin2b - sin2b.sin2a = 0
Similar questions