Question

sin^2alpha +sin^2beta+sin^2gama=cos^2alpha+cos^2beta+cos^2gama=3/2​

Answer 1

Answer:

Note: cos^2(x)=1-sin^2(x)

hence,

sin^2(alpha)+sin^2(beta)+sin^2(gama)=1-sin^2(alpha)+1-sin^2(beta)+1-sin^2(gama)

2(sin^2(alpha)+sin^2(beta)+sin^2(gama))=3

sin^2(alpha)+sin^2(beta)+sin^2(gama)=3/2

Step-by-step explanation: