Question

Sin - 2sin ^3 / 2cos^2 - cos = tan

Answer 1

Explanation:

ANSWER

By solving LHS we get

⇒cosA(2cos2A−1)sinA(1−2sin2A)

=tanA(cos2Acos2A) [∵1−2sin2A=cos2A2cos2A−1=cos2A]

=tanA=RHS

Hence Proved.

Answer 2

Explanation:

Given sin theta – 2 sin ^3 theta ) / (2 cos^3 theta – cos theta = tan theta

• Given (sin theta – 2 sin ^3 theta ) / (2 cos^3 theta – cos theta )
•        = sin theta (1 – 2 sin^2 theta) / cos theta (2 cos ^2 theta – 1)
•       = sin theta (1 – 2 (1 – cos^2 theta ) / cos theta (2 cos^2 theta – 1)
•       = sin theta (1 – 2 + 2 cos ^2 theta ) / cos theta (2 cos^2 theta – 1)
•     = sin theta ( 2 cos^2 theta – 1) / cos theta (2 cos^2 theta – 1)
•        = sin theta / cos theta
•        = tan theta  

Reference link will be

https://brainly.in/question/878295