Sin^2x + cos^2x = 1 proof in short
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Answered by
2
Take a right angle triangle ABC with ∠B = 90°. So AC is the hypotenuse.
So Pythagoras theorem says: AB² + BC² = AC² --- (1)
Sin A = BC /AC Cos A = AB/AC by definition.
Sin² A + cos² A = BC²/AC² + AB² / AC² = 1 using (1).
proved.
So Pythagoras theorem says: AB² + BC² = AC² --- (1)
Sin A = BC /AC Cos A = AB/AC by definition.
Sin² A + cos² A = BC²/AC² + AB² / AC² = 1 using (1).
proved.
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Answered by
1
Use Pythagorean Theorem:
We know,
In the right triangle,
Cosθ =
Sinθ =
where h means horizontal
v means vertical
r means hypotenuse
∴ Pythagorean Theorem,
r² = v²+h² = r²sinθ + r²cos²θ ⇔ cos²θ+sin²θ = 1
We know,
In the right triangle,
Cosθ =
Sinθ =
where h means horizontal
v means vertical
r means hypotenuse
∴ Pythagorean Theorem,
r² = v²+h² = r²sinθ + r²cos²θ ⇔ cos²θ+sin²θ = 1
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