Question

sin 3θ= cos(θ-6°) and 3θ and θ-6° are acute angles, find value of θ.

Answer 1

hey mate

here is your answer

we know that,

sin a=cos (90-a)

thus,

sin 3 theta=sin (90-(theta-6))

sin 3 theta=sin(90-theta+6)

=>3 theta=96-theta

=>4 theta=96

=>theta=96/4

=>24(answer)

Answer 2

Answer:

24

Step-by-step explanation:

sin a=cos (90-a)

thus,

sin 3 θ=sin (90-(θ-6))

sin 3 θ=sin(90- θ +6)

=>3 θ=96-θ

=>4 θ=96

=>θ =96/4

=>24° is the angle