sin 30 degree + tan 45 degree - cosec 60 degree divided by sec 30 degree + cos 60 degree +cot 45 degree solve
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here is your answer it is correct
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Given:
sin 30° + tan 45° - cosec 60° divided by sec 30° + cos 60° + cot 45°
To Find:
Solve the above.
Solution:
Here, we have
(sin 30° + tan 45° - cosec 60°) ÷ (sec 30° + cos 60° + cot 45°)
The above expression can be written by substituting their values as
(1/2 + 1 - 2/√3) ÷ (2/√3 + 1/2 + 1) = {(√3 + 2√3 - 4)/2√3 ÷ (4 + √3 + 2√3)/2√3)}
= {(3√3 - 4)/(3√3 + 4)} x {(3√3 - 4)/(3√3 - 4)}
= (27 + 16 - 24√3) / (27 - 16)
= (43 - 24√3) / 11
Hence, sin 30° + tan 45° - cosec 60° divided by sec 30° + cos 60° + cot 45° can be solved as (43 - 24√3) / 11.
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