Sin 30 + tan 45 - cosec 60
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0
(1/2)+1-(2/√3)
= √3+2√3-4/2√3
=3√3-4/2√3
=9-4√3/6 Answer
= √3+2√3-4/2√3
=3√3-4/2√3
=9-4√3/6 Answer
Answered by
3
sin30 = ½
tan 45 = 1
cosec 60 = 2/√3
sin30+tan45-cosec60
= ½+1-2/√3
=3/2 - 2/√3
=3√3-4/2√3
tan 45 = 1
cosec 60 = 2/√3
sin30+tan45-cosec60
= ½+1-2/√3
=3/2 - 2/√3
=3√3-4/2√3
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