Question

(Sin 30+tan 45-cosec 60)÷(sec 30+ cos 60+ cot 45)

Answer 1

Answer:

Step-by-step explanation:

(Sin 30 + tan 45- cosec 60)= (1/2+1-2/√3)= (√3+2√3-4)/2√3

Now,

(Sec 30 + cos 60 + Cot 45)

= (2/√3+1/2+1)

= (4+√3+ 2√3)/2√3

Now dividing we get,

(√3+2√3-4)/(√3+2√3+4)

(√3(3)-4)/(√3(3)+4)

Rationalising , we get,

(3√3-4)(3√3-4)/(3√3+4)(3√3-4)

27-24√3+16/27-16

(43-24√3)/11.

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