Question

sin 30°+ cota45°- sin 60°+ cos30°
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cos 45+ sec 60°- tan 45º+ sin 90°
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Answer 1

Answer:

= (1/2) /(1/√2) +1/2 - (√3/2 ) /1 + (√3/2) /1

= √2/2 + 1/2 - √3/2 + √3/2

= √2+1/2

Hope it's help you

Answer 2

given=>

sin 30°+ cot45°- sin 60°+ cos30°

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cos 45+ sec 60°- tan 45º+ sin 90°

to find=>

sin 30°+ cot45°- sin 60°+ cos30°=?--(1

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cos 45+ sec 60°- tan 45º+ sin 90°=? --(2

solution=>

We know that

$\sin(30) = \frac{1}{2} \\ \\ \cot(45) = 1 \\ \\ \sin(60) = \frac{ \sqrt{3} }{2} \\ \\ \cos(30) = \frac{ \sqrt{3} }{2} ...(3$

equition (3 value put on (1

$= \frac{1}{2} + 1 - \frac{ \sqrt{3} }{2} + \frac{ \sqrt{3} }{2} \\ \\ = \frac{1}{2} + 1 \\ \\ = \frac{3}{2}$

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we know that

$\\ \\ \cos(45) = \frac{1}{ \sqrt{2} } \\ \\ = \sec(60) = 2 \\ \\ \tan(45) = 1 \\ \\ \sin(90) = 1 \: \: \: \: ....(4$

eqution (4 value put on equition (2

$= \frac{1}{ \sqrt{2} } + 2 - 1 + 1 \\ \\ = \frac{1}{ \sqrt{2} } + 2 \\ \\ = \frac{1 +2 \sqrt{2} }{ \sqrt{2} }$

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answer

sin 30°+ cot45°- sin 60°+ cos30°=

$= \frac{3}{2}$

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cos 45+ sec 60°- tan 45º+ sin 90°=

$= \frac{1 + 2 \sqrt{2} }{ \sqrt{2} }$

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I hope it help you❤