Math, asked by ranjanrohan250, 11 months ago

(sin 30° + tan 45º - cosec 60°)/
(sec 30° + cos 60° + cot 45°)​

Answers

Answered by Anonymous
1

 =  \frac{ \sin(30)  +  \tan(45) -  \csc(60)  }{ \sec(30) +  \cos(60)  +  \cot(45)  }  \\  =  \frac{ \frac{1}{2} + 1 +  \frac{2}{ \sqrt{3} }  }{ \frac{2}{ \sqrt{3} }  + 1 +  \frac{1}{2}  }  \\  = 1

hope it helps you

Answered by praveensmartysingh81
0

Answer:

(sin30°+tan45°-cosec60°) / (sec30°+cos60°+cot45°)

(1/2 + 1 - 2/√3) / (2√3 + 1 + 1/2)

= 1 ans...

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