Question

Sin 30°17'/cos 59°43'

Answer 1

please see the attachment

Answer 2

$\dfrac{\sin 30°17'}{\sin 30°17'}=1$

Step-by-step explanation:

We have,

$\dfrac{\sin 30°17'}{\cos 59°43'}$

To find, the value of $\dfrac{\sin 30°17'}{\cos 59°43'}=?$

∴ $\dfrac{\sin 30°17'}{\cos 59°43'}$

We know that,

60' = 1 °

⇒ 1' =$\dfrac{1}{60}$°

$=\dfrac{\sin 30°17'}{\cos (90-30°17')}$

Using trigonometric identity,

$\cos (90-A)=\sin A$

$=\dfrac{\sin 30°17'}{\sin 30°17'}$

= 1

Thus, $\dfrac{\sin 30°17'}{\sin 30°17'}=1$