Question

sin^3A + cos^3A= (sinA+cosA) (1-3sinAcosA)​

Answer 1

Answer:

sin^3A + cos^3A

we know a^3 +b^3= (a+b) (a^2-ab+b^2)

then sin^3 +cos^3= (SinA+sinB) sin^2a-sinAcosA+cos^2A)

=(sinA+cosA) (1-sinAcoaA).

as cos^2+sin^2=1

= (sinA+cosA) (1-sin^2A/2)

as sin2A= 2sinA cosA

HENCE PROVED

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