sin 3A = cos 6 A then A = ?
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Answer:
sin 3A = cos 6 A
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Secondary School Math 13 points
If sin 3a = cos (a-6) where 3a and a-6 are both
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jaismeen8103
I think question is like this ,
Sin3A = Cos ( A - 6 ) , where 3A and A - 6 are both acute angle then find value of A.
Solution---> ATQ,
Sin3A = Cos ( A - 6 )
We have a formula
Cosθ = Sin ( 90° - θ ) , applying it we get,
=> Sin3A = Sin { 90° - ( A - 6 ) }
=> Sin3A = Sin ( 90° - A + 6 )
=> 3A = 90° - A + 6
=> 3A + A = 96
=> 4A = 96
=> A = 96 / 4
=> A = 24°
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