Question

Sin 3theta=cos(theta-26°) where 3 theta and theta -26° are acute angles ..find value of theta

Answer 1

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Answer 2

Answer:

let theta = A

Sin 3 A = cos ( A - 26° )

Therefore,

Sin 3 A = sin ( 90° - A + 26° )

Sin 3 A = sin ( 116 - A )

By equating both we get,

3 A = 116° - A

4 A = 116°

A = 29°

Therefore A° = 29°

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