Question

(sin 3x/cos x)+(cos 3x / sin x)= 2 cot 2x
prove it​

Answer 1

Answer:

Ans= (sin3x+cos3x)(cosx+sinx)^3(sin3x+cos3x)(cosx+sinx)

3

Step-by-step explanation:

cos(x) appears thrice, and so does sin(x).

so=

\begin{gathered}sin(3x)cos(x)cos(x)cos(x)+cos(3x)sin(x)sin(x)sin(x) \\ sin(3x)(cos(x))^3+cos(3x)+(sin(x))^3 \\ (sin3x+cos3x)(cosx+sinx)^3\end{gathered}

sin(3x)cos(x)cos(x)cos(x)+cos(3x)sin(x)sin(x)sin(x)

sin(3x)(cos(x))

3

+cos(3x)+(sin(x))

3

(sin3x+cos3x)(cosx+sinx)

3

Ans= (sin3x+cos3x)(cosx+sinx)^3(sin3x+cos3x)(cosx+sinx)

3