Question

sinα=4/5 and cosβ=12/13,then find the value of sinαcosβ+cosαsinβ

Answer 1

Answer:

if sin(alpha) = 4/5, then cos(alpha) = 3/5 and if cos(beeta) = 12/13, then sin(beeta) = 5/13.

Thus, sin(alpha)cos(beeta) + cos(alpha)sin(beeta)

= (4/5)*(12/13) + (3/5)*(5/13)

=(48 + 15)/65

=63/65

Answer 2

hope it will help you