Question

sin^ 4 theta +sin^ 2 theta cos ^2 theta sin^2theta​

Answer 1

To prove:

sin⁴x + sin²xcos²x=sin²x

LHS:

sin⁴x + sin²xcos²x

=sin²x(sin²x+cos²x)

We know that,

sin²∅+cos²∅=1

=sin²x(1)

=sin²x

=RHS

Hence,proved