sin 45 cos 30 -cos 45 sin 30
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1/√2 × √3/2 - 1/√2 - 1/2
= 1/√2 ( (√3-1)/2)
= (√3-1)/2√2= (1.732-1)/2√2 = 0.732/2√2 = 0.517
= 1/√2 ( (√3-1)/2)
= (√3-1)/2√2= (1.732-1)/2√2 = 0.732/2√2 = 0.517
shruti9364:
answer is wrong
Answered by
4
HEY Buddy.....!! here is ur answer
sin45°cos30°– cos45°sin30°
[ As we know that : sin45° = 1/√2, cos45° = 1/√2
sin30° = 1/2 and cos30° = √3/2 ]
=> (1/√2)(√3/2) – (1/√2)(1/2)
=> (√3/2√2) – (1/2√2)
=> (√3–1)/2√2 <<<Ans.
I hope it will be helpful for you....!!
THANK YOU ✌️✌️
sin45°cos30°– cos45°sin30°
[ As we know that : sin45° = 1/√2, cos45° = 1/√2
sin30° = 1/2 and cos30° = √3/2 ]
=> (1/√2)(√3/2) – (1/√2)(1/2)
=> (√3/2√2) – (1/2√2)
=> (√3–1)/2√2 <<<Ans.
I hope it will be helpful for you....!!
THANK YOU ✌️✌️
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