sin 45 +cos 45/tan 60
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Answered by
4
Hey!!!!
sin45 + cos45/tan60
=> 1/√2 + 1/√2/√3
=> 1/√2 + 1/√6
=> (√2 + √6)/√12
=>(√2 + √6)/2√3
Now rationalize it
Hope this helps
sin45 + cos45/tan60
=> 1/√2 + 1/√2/√3
=> 1/√2 + 1/√6
=> (√2 + √6)/√12
=>(√2 + √6)/2√3
Now rationalize it
Hope this helps
Answered by
2
sin 45 = 1/\sqrt{2} and cos 45 = 1/\sqrt{2}
so 1/root2+1/roo2 = 2/root2
tan 60 = root3
so answer = (2/root2)/root3
so 2/root 6
so 1/root2+1/roo2 = 2/root2
tan 60 = root3
so answer = (2/root2)/root3
so 2/root 6
goodday:
i could not place the square roots i have mentioned them
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