Question

sin 48.sec 42 + cos 48.cosec 42 =2 prove that

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

$The \: value \: of \:\\ sin48sec42+cos48cosec42\\=2$

Step-by-step explanation:

$The \: value \: of \:\\ sin48sec42+cos48cosec42\\</p><p>=sin(90-42)sec42\\+cos(90-42)cosec42\\</p><p>=cos42sec42+sin42cosec42\\</p><p>=cos42\times \frac{1}{cos42}+sin42\times \frac{1}{sin42}\\</p><p>=1+1$

Therefore,

$The \: value \: of \:\\ sin48sec42+cos48cosec42\\=2$

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