(Sin 49/ Cos 41 - Cos 17/ Sin 73)=?
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since, sin (90-A)=cos A
sin (90-49) = cos 41 ,
similarly, sin (90-73)= cos 17
so cos41/cos41-cos17/cos 17= 0 (answer)
sin (90-49) = cos 41 ,
similarly, sin (90-73)= cos 17
so cos41/cos41-cos17/cos 17= 0 (answer)
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