Math, asked by rakesh3009, 1 year ago

sin 50 cos 85 = (1 - √2 sin 35)/2√2

Answers

Answered by knjroopa
52

Answer:

proved

Step-by-step explanation:

Given sin 50 cos 85 or we can take as

     cos 85 sin 50 multiply and divide by 2

 So 1 /2 x 2 sin 50 cos 85    

We have the formula 2 cos A sin B = sin(A + B) - sin (A - B)

                                               50 + 85 = 135 and 85 - 50 = 35

                   1 / 2 ( sin 135 - sin 35)

                    1 / 2(sin (90 + 45) - sin 35

                      sin(90 + a) = cos a

                    1/2 (cos 45 - sin 35)

                   1/2 (1 /√2 - sin 35)

                 1/2 (1 - √2 sin 35) /2√2 (proved)

Answered by talwarmohit2005
12

Answer:

Step-by-step explanation:

Given sin 50 cos 85 or we can take as

     cos 85 sin 50 multiply and divide by 2

 So 1 /2 x 2 sin 50 cos 85    

We have the formula 2 cos A sin B = sin(A + B) - sin (A - B)

                                               50 + 85 = 135 and 85 - 50 = 35

                   1 / 2 ( sin 135 - sin 35)

                    1 / 2(sin (90 + 45) - sin 35

                      sin(90 + a) = cos a

                    1/2 (cos 45 - sin 35)

                   1/2 (1 /√2 - sin 35)

                 1/2 (1 - √2 sin 35) /2√2

Hope it helps

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