Math, asked by Natsumi, 1 year ago

sin (50° + A) - cos (40° - A) + tan 1° × tan 10° × tan 20° × tan 70° × tan 80° × tan 89°

Answers

Answered by kinkyMkye
8
sin(50+A) = cos(90-50-A) cos(40-A)
tanα = cot(90-α) ⇒ tanα tan(90-α) = 1

 hence 
Sin (50° + A) - cos (40° - A) + tan 1° × tan 10° × tan 20° × tan 70° × tan 80° × tan 89° = 1
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