∫ sin(5x/2) /sin(x/2)
is equal to:
(where c is a constant of integration).
(A) x + 2sin x + 2sin2x + c (B) 2x + sinx + 2sin2x + c
(C) x +2sinx + sin2x + c (D) 2x + sinx + sin2x + c
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∫ sin(5x/2) /sin(x/2) is equal to (C) x +2sinx + sin2x + c
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∫sin(5x/2)/sin(x/2) is equal to (c)x+2sinx+sin2x+c
1.Let I=∫sin(5x/2)/sin(x/2)
=∫(2sin5x/2cosx/2)/2sinx/2cosx/2
[multiplying by 2cosx/2 in numerator and denominator]
2.
=∫(sin3x+sin2x)/sinxdx
=[therefore 2sinAcosB=sin(A+B)+sin(A-B) and sin2A=2sinAcosA]
3.=∫(3sinx-4sin³x)+2sinxcosx/sinxdx
=∫(3-4sin²x+2cosx)dx
=∫[(3-2(1-cos2x)+2cosx]dx
=integration of [1+2cos2x+2cosx]dx
=x+2sinx+sin2x+C(integration of 1 is x
integration of 2cos2x is 2sinx
integration of 2cosx is sin2x)
therefore after applying all the integrations we get = x+ 2sinx+sin2x + c
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