Sin (60+A) cos(30-B) + cos(60+A) sin(30-B)= cos(A+B)
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Sin (60+A) cos(30-B) + cos(60+A) sin(30-B)
=Sin{(60+A)+(30-B)}=Sin{90+A-B}=cos (A-B)
∵sin(90+x)=cosx
=Sin{(60+A)+(30-B)}=Sin{90+A-B}=cos (A-B)
∵sin(90+x)=cosx
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