sin (60°+theta) + sin(60°- theta)
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Answer:
√3 cos theta
Step-by-step explanation:
sin(60+theta) = sin60•cos theta + sin theta•cos60
=√3/2cos theta + 1/2sin theta
= (√3cos theta + sin theta)/2
sin(60-theta) = (√3cos theta - sin theta)/2
ACQ,
= sin(60+theta) + sin(60-theta)
=(√3cos theta + sin theta)/2 + (√3cos theta - sin theta)/2
=( √3cos theta + sin theta + √3cos theta -sin theta)/2
= 2√3cos theta / 2
= √3 cos theta
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