Math, asked by savitaadiwal20, 1 year ago

Sin 63 cod 27+cos63 sin 27=1

Answers

Answered by divya886
2

heyy mate!!!! here is ur answer

Sin 63 cos 27 + cos 63 sin 27= 1

LHS

sin 63 cos(90-63) + cos 63 sin(90-63)

sin 63 * sin 63 + cos 63 * cos 63

sin^2 63 + cos ^2 63 =1     [sin^2 theta + cos^ theta=1]

.therefor, L.H.S= R.H.S

hope it will help u if it is then plz mark mine answer as the brainliest one




suganthy1963: Sin (A+B) = Sin A Cos B + Cos A Sin B
suganthy1963: Sin (63+27) = Sin 90= 1
smartysurya773389: hey
Answered by Anonymous
4
sɪɴ63 ᴄᴏs27 +ᴄᴏs63 sɪɴ27 =1

sɪɴ(90-27)ᴄᴏs 27 + ᴄᴏs(90-27)sɪɴ27= 1

ᴄᴏs27 ᴄᴏs27 + sɪɴ27 sɪɴ27 =1

 {cos}^{2} 27 + {sin}^{2} 27 = 1
1=1

ʟʜs =ʀʜs

naveen00754: hlo
Similar questions