sin^6A+cos^6A = 1 - 3sin^2Acos^2A
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sin^6A + cos^6A = (sin²)³ + (cos²)³
= ( sin² + cos² )³ - 3( sin².cos² ) (sin² + cos² )
= 1 - 3sin²cos² × 1
= 1 - 3sin²cos²
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Answered by
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Answer: L.H.S=sin^6a + cos^6a
(sin^2a)^3 + (cos^2a)^3
(sin^2a+cos^2a)^3-3(sin^2a+cos^2a)(sin^2a+cos^2a)
1-3sin^2a+cos^2a*1
1-3sin^2a+cos^2a
Step-by-step explanation:
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