sin ^6theta + cos^6theta + 3 sin^2theta × cos^2 theta?
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Answer:
This answer is 1.
Step-by-step explanation:
sin^6 theta + cos^6 theta + 3 sin^2 theta × cos^2 theta
= (sin^2 theta)^3 + (cos^2 theta)^3 + 3 sin^2 theta × cos^2 theta (sin^2 theta + cos^2 theta) [We know, (a+b)^3 = a^3 + b^3 + 3ab (a+b) ]
= (sin^2 theta + cos^2 theta)^3
= (1)^3 [We know, (sin^2 theta + cos^2 theta) = 1]
= 1
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