Math, asked by ramakrishnag3105, 6 months ago

A can do a work in 12 days and B finish the same work in 24 days. If they work together, in how many days will they compete the work​

Answers

Answered by hariharan11122006
6

Step-by-step explanation:

Its stated that,

In 24 days Ashu can do the work.

∴ In 1 day Ashu can do = (1/24) parts of the work.

In 12 days Nakul can do the work.

∴ In 1 day Nakul can do = (1/12) parts of the work.

∴ In 1 day Ashu and Nakul together can do_

(1/12) + (1/24)

= (2+1) /24 [∴ The L.C.M. of 12 and 24 is 24.]

= 3/24

= 1/8 parts of the work.

∴ In 1 day they together can do 1/8 parts of the work.

∴ In 6 days they together can do = (6*1/8)

                                                       = 3/4 parts of the work.

∴ In 6 days they together can do 3/4 parts of the work.

So, after working for 6 days together the part of work remains_

(1-3/4)

= (4-3)/4 [The L.C.M. is 4.]

= 1/4 parts of the work.

According to the question Nakul left after working for 6 days and the remain part of work is done by Ashu.

As, we get earlier,

1/24 parts of the work can be done by Ashu in 1 day.

∴ 1 part of the work can be done by Ashu in 24 days

∴ 1/4 parts of the work can be done by Ashu in (24*1/4)

                                                                             = 6 days.

So, it will take 6 days to complete the remaining work.

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Answered by Guntezkaur
0

Answer:

answer is 6

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