A can do a work in 12 days and B finish the same work in 24 days. If they work together, in how many days will they compete the work
Answers
Step-by-step explanation:
Its stated that,
In 24 days Ashu can do the work.
∴ In 1 day Ashu can do = (1/24) parts of the work.
In 12 days Nakul can do the work.
∴ In 1 day Nakul can do = (1/12) parts of the work.
∴ In 1 day Ashu and Nakul together can do_
(1/12) + (1/24)
= (2+1) /24 [∴ The L.C.M. of 12 and 24 is 24.]
= 3/24
= 1/8 parts of the work.
∴ In 1 day they together can do 1/8 parts of the work.
∴ In 6 days they together can do = (6*1/8)
= 3/4 parts of the work.
∴ In 6 days they together can do 3/4 parts of the work.
So, after working for 6 days together the part of work remains_
(1-3/4)
= (4-3)/4 [The L.C.M. is 4.]
= 1/4 parts of the work.
According to the question Nakul left after working for 6 days and the remain part of work is done by Ashu.
As, we get earlier,
1/24 parts of the work can be done by Ashu in 1 day.
∴ 1 part of the work can be done by Ashu in 24 days
∴ 1/4 parts of the work can be done by Ashu in (24*1/4)
= 6 days.
So, it will take 6 days to complete the remaining work.
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Answer:
answer is 6
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