sin^6theta+cos^6theta+3sin^2thetacos^2theta=1
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Step-by-step explanation:
Consider, sin⁶ө + cos⁶ө =1-3sin²ө cos²ө
(sin²ө)³+ (cos²ө)³ = (sin²ө + cos²ө)³ − 3 (sin²ө cos²ө)(sin²ө + cos²ө)
[since a³ + b³ = (a+b)³− 3ab(a+b)]
= 1 − 3sin²ө cos²ө [Since sin²ө + cos²ө = 1]
kalaisiva4132:
Hope this helps :)
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