sin^6x+cos^6x=1-3sin^2xcos^2x
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Given sin^6x + cos^6x can be written as
= (sin^2 x)^3 + (co^2 x)^3
We know that a^3 + b^3 = (a+b)^3 - 3ab(a+b)
= (sin^2x+cos^2x)^3 - 3sin^2xcos^2x(sin^2x+cos^2x)
= 1 - 3sin^2xcos^2x.
Hope it helps!
= (sin^2 x)^3 + (co^2 x)^3
We know that a^3 + b^3 = (a+b)^3 - 3ab(a+b)
= (sin^2x+cos^2x)^3 - 3sin^2xcos^2x(sin^2x+cos^2x)
= 1 - 3sin^2xcos^2x.
Hope it helps!
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