sin^6x+cos^6x=1-3sin^3xcos^2x
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question is wrong....right question is
sin^6x+cos^6x=1-3sin^2xcos^2x
whose solution is
(sin^2x+cos^2x)^3=sin^6x+cos^6x+3sin^2x.cos^2x.(sin^2x+cos^2x).
1=sin^6x+vos^6x+3sin^2xcos^2x
solve it
sin^6x+cos^6x=1-3sin^2xcos^2x
whose solution is
(sin^2x+cos^2x)^3=sin^6x+cos^6x+3sin^2x.cos^2x.(sin^2x+cos^2x).
1=sin^6x+vos^6x+3sin^2xcos^2x
solve it
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