sin(70+0) - cos(20-0)
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sin(70+0)-cos(20-0)=0
=0.94-0.94
=0
sin(70+theta)-cos(20-theta)
=sin(90-70+theta)-cos(20-theta)
=sin(90-(70-theta)-cos(20-theta)
=cos(20-theta)-cos(20-theta) since:sin(90-theta)=cos theta
Is it clear for you
=0
=0.94-0.94
=0
sin(70+theta)-cos(20-theta)
=sin(90-70+theta)-cos(20-theta)
=sin(90-(70-theta)-cos(20-theta)
=cos(20-theta)-cos(20-theta) since:sin(90-theta)=cos theta
Is it clear for you
=0
ammusowji131:
I edit the answer see that
actually its theta not 0
ohh...... your question is not clear
sin(70+theta) - cos(20-theta)=0
prove
is it clear now?
kk wait
see the answer
thanks
Wlcm
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