sin 70°-cos40/cos50-sin20
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(sin 70 + cos 40) / (cos 70 + sin 40)
= (sin 70 + sin 50) / (cos 70 + cos 50)
= (sin(60+10) + sin(60-10)) / (cos(60+10) + cos(60-10))
= 2sin60cos10/(2cos60cos10)
= tan60
=
= (sin 70 + sin 50) / (cos 70 + cos 50)
= (sin(60+10) + sin(60-10)) / (cos(60+10) + cos(60-10))
= 2sin60cos10/(2cos60cos10)
= tan60
=
ammusrividya24:
but 0 is the ans
no its root of 3
thats the answer
noo
sryy..its 1/√3
okk
please can you give this ans d/dx (secx+tanx/secx-tanx)
Answered by
3
Answer:
1/√3
Step-by-step explanation:
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