sin^8a-cos^8a please answer me anybody
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sin^8 A - cos^8 A
= ( sin^4 A + cos^4 A)( sin^4 A - ccos4 A)
= ( sin^4 A + cos^4 A + 2 sin^2A cos^2A - 2 sin^2A cos^2A)( sin^2 A + cos^2 A)( sin^2 A- cos^2 A)
= { ( sin^2 A +cos^2 A)-2sin^2Acos^2A}(-cos2A)
={1- (sin^2 2A)/2}(-cos 2A)
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= ( sin^4 A + cos^4 A)( sin^4 A - ccos4 A)
= ( sin^4 A + cos^4 A + 2 sin^2A cos^2A - 2 sin^2A cos^2A)( sin^2 A + cos^2 A)( sin^2 A- cos^2 A)
= { ( sin^2 A +cos^2 A)-2sin^2Acos^2A}(-cos2A)
={1- (sin^2 2A)/2}(-cos 2A)
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