Math, asked by glad123, 11 months ago

(sin 90 +cos 60 +cos 45)*(sin30 - cos 0 +cos 45 )​

Answers

Answered by mysticd
2

Solution:

(sin 90 +cos 60 +cos 45)*(sin30 - cos 0 +cos 45 )

= [1+(1/2)+1/√2]*[1/2-1+1/√2]

= (1/2+1/√2+1)(1/2+1/√2-1)

= (1/2+1/√2)² - 1²

= [(√2+2)/√2]² - 1

= (√2)²+2²+2*√2*2 - 1

= 2+4+4√2-1

= 5+4√2

••••

Answered by nalinsingh
1

Hey !

Refer the below attachment !

Thanks !

Attachments:
Similar questions