Math, asked by preetham7016, 1 year ago

sin(90+theta)+cos( 270-theta)/cot(180+theta)+ tan(360-theta)

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Answered by Anonymous

1

Sin(180°+θ)cos(90°°+θ)tan(270°+θ)cot(360°+ θ)/sin(360°-θ)cos(360°+θ)cosec(-θ)sin(270°+ θ)=-sinθ.sinθ.(-cotθ).cotθ/(-sinθ).cosθ.

preetham7016: wrong answer

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