Math, asked by Ayessha, 7 months ago

sin (90°-theta) /1+sin theta+cos theta/1-cos (90-theta) =2sec theta

Answers

Answered by sandy1816
2

Step-by-step explanation:

sin(90-A)/1+sinA + cosA/1-cos(90-A)

=cosA/1+sinA +cosA/1-sinA

=cosA[1-sinA+1+sinA/1-sin²A]

=cosA[2/cos²A]

=2/cosA

=2secA

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