sin 90degrre is proved
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Consider a right angled triangle with angles x, y, 90° .
We know that, sinΦ = opposite side to Φ / hypotenuse .
So, Consider sin90 , we know that hypotenuse is the opposite to 90°
By the definition , sin90=opposite to 90/hypotenuse
Which reduces sin90= hypotenuse / hypotenuse
sin90=1
Hence, we proved that sin90=1
We know that, sinΦ = opposite side to Φ / hypotenuse .
So, Consider sin90 , we know that hypotenuse is the opposite to 90°
By the definition , sin90=opposite to 90/hypotenuse
Which reduces sin90= hypotenuse / hypotenuse
sin90=1
Hence, we proved that sin90=1
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