(sin A -1) (2 cos A-1)=0
Prashantsingh4576:
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Answer:
2[sin(A-1)][cos(A-1)]
Step-by-step explanation:
=>It is in form 2sinxcosx=sin2x
=>sin2(A-1)=0
=>sin2(A-1)=sin0°
=>2(A-1)=0 =>A=1
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