Question

sin A=1 / 2 tan^2 45 degrees where A is an acute angle then find the value of A

Answer 1

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by
Ankita

Answer 2

Sin^2 A = 1/2 tan^2A= 1/(2*(1)^2) =1/2, As angle A is an acute angle.

So,

SinA = 1/√2 , You know value of sin 45°=1/√2

Or,

A = Sin^(-1) {1/√2} = 45°

So, A = 45°