Question

Sin A = 1/3 ,so find value of cosA and Tan B .

Answer 1

Answer:

$\sin(a) = \frac{1}{3} = \frac{p}{h} \\ by \: using \: pgt \\ {h}^{2} = {p}^{2} + {b}^{2} \\ {3}^{2} = {1}^{2} + {b}^{2} \\ 9 = 1 + {b}^{2} \\ {b}^{2} = 9 - 1 = 8 \\ b = \sqrt{8} \\ \cos(a) = \frac{b}{h} = \frac{ \sqrt{8} }{3} \\ \tan(a) = \frac{p}{b} = \frac{1}{ \sqrt{8} } \: ans \\ \\ \\ mark \: brainliest$