sin A/1 - Cos A = 1 + Cos A - Sin A/ Sin A - 1 + Cos A
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..To prove,
....sinA/1+cosA=1-cosA/sinA
L.H.S=sinA/1+cosA
rationalise the denominator of the L. H. s..
sinA×(1—cosA)/(1+cosA)×(1—cosA)
using the property (a+b)(a–b) =a²–b²
sinA(1—cosA) /(1)²—(cos)²
sinA(1—cosA) /(1—cos²A)
using the property (1–cos²A) =sin²A
sinA(1—cos A) /Sin²A
SinA(1—cosA) /sinA×sinA
(1—cosA) /sinA=L.H.S....... proved...
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