Math, asked by mark214, 10 months ago

sin A+1-cos A/cos A-1+sin A=1+sin A÷cos A

Answers

Answered by bantipadhan2004

2

Answer:

LHS = cosA / 1+sinA + 1+sinA / cosA =(cos^2A+1+sin^2A+2sinA ) /cosA(1+sinA) = (2+2sinA) / cosA(1+sinA) = {2(1+sinA)} / cosA (1+sinA)

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