sin A/1+cos A =tan A /2
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Answered by
3
sinA = 2sin(A/2)cos(A/2)
cosA = 2cos^2 (A/2) - 1
sinA / (1+cosA) = sin(A/2) / cos(A/2) = tan(A/2)
cosA = 2cos^2 (A/2) - 1
sinA / (1+cosA) = sin(A/2) / cos(A/2) = tan(A/2)
panbaf2288:
2Sin(A/2)cos(A/2)/2 cos(A/2) cos(A/2) = sin(A/2)cos(A/2)= tan(A/2)
Answered by
4
sin A = 2 sin (A/2) cos (A/2)
1 + cos A = 2 cos^2 (A/2)
Therefore,
sin A / ( 1 + cos A )
=2 sin (A/2) cos (A/2) / 2 cos^2 (A/2)
= tan (A/2)
1 + cos A = 2 cos^2 (A/2)
Therefore,
sin A / ( 1 + cos A )
=2 sin (A/2) cos (A/2) / 2 cos^2 (A/2)
= tan (A/2)
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