Math, asked by neerajtiwari6, 11 months ago

sin A(1 + tan A) + COS A(1 + cot A) = sec A+ cosec A.

Answers

Answered by samir4934

Step-by-step explanation:

L.H.S =cosA(1+cosA/sinA)+sinA(1+sinA/cosA) =cosA+[(cosA)(cosA)]/sinA+sinA+[(sinA)(sinA)]/cosA =cosA+[(sinA)(sinA)]/cosA+[(cosA)(cosA)]/sinA+sinA ={[(cosA)(cosA)]+[(sinA)(sinA)]}/cosA+{[(sinA)(sinA)]+[(cosA)(cosA)]}/sinA =1/cosA+1/sinA =secA+cosecA=R.H.S hence prooved

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