Question

sin(A-18°) = cos2A solve it plz​


find the value of A

Answer 1

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$\color{red}\huge{\underline{\underline{\mathfrak{Answer}}}}$

sin(A-18°) = cos2A

sin(A-18°) =sin(90°-2A)

By comparing

A-18 = 90°-2A

A +2A =90° +18°

3A =108 °

A =108/3

A = 36°

$\fcolorbox{black}{white}{A=36°}</font>$

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Hope it helps

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