Sin A + 2 cos A = 1 then prove that 2 sin A minus cos A = 2
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Answered by
14
As sin + 2cos = 1
By squaring
sin² + 4cos² + 4 *sin * cos =1
(1-cos²) + 4* (1- sin²) + 4* sin * cos = 1
1 - cos² + 4 - 4* sin² + 4* sin * cos = 1
By multiplying both sides by -1, we get
cos² - 4 + 4* sin² - 4 * sin * cos = 0
cos² + 4* sin² - 4* sin * cos = 4
(2 * sin - cos )² = (2)²
Square root both the side
Therefore 2sin - cos = 2
(proved)
plz mark as brainiest
By squaring
sin² + 4cos² + 4 *sin * cos =1
(1-cos²) + 4* (1- sin²) + 4* sin * cos = 1
1 - cos² + 4 - 4* sin² + 4* sin * cos = 1
By multiplying both sides by -1, we get
cos² - 4 + 4* sin² - 4 * sin * cos = 0
cos² + 4* sin² - 4* sin * cos = 4
(2 * sin - cos )² = (2)²
Square root both the side
Therefore 2sin - cos = 2
(proved)
plz mark as brainiest
Answered by
8
Answer:
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Step-by-step explanation:
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