Math, asked by ratanamaladas, 8 months ago

sin A - 2 sin^3 A/
2 cos^3 A - cos A = tan A​

Answers

Answered by Anonymous
2

Step-by-step explanation:

SinA(1 - 2Sin²A)/CosA(2Cos²A - 1)

SinA*Cos2A/CosA*Cos2A

SinA/CosA = tanA

Answered by Anonymous
2

Answer:

sin a -2sin ^3 a/ 2cos^3 a + cos a

=sin a (1-2sin^2a)/ cos a ( 2cos2a+1)

=sin a/cos a × 1-2sin2a/2cos2a+1

=tan a × 2(1-sin2a)/2(1-sin2 a)+1

=tana ×1/1

=tan a=RHS

it will help you...i m a teacher and the answer is correct

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